The depth `d`, at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)

Options

A. `R/n`
B. `R((n-1)/n)`
C. `R/(n^2)`
D. `R(n/(n+1))`

Answer

B

Explanation

`g.=g(1-d/R)`
`rArrg/n=g(1-d/R)rArrd/R=1-1/h`
`rArrd=R((n-1)/n)`