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The height a which the weight of a body ...

The height a which the weight of a body becomes `1//16th` its weight on the surface of earth (radius `R`) is

A

5R

B

15R

C

3R

D

4R

Text Solution

Verified by Experts

The correct Answer is:
C
`g.=g/((1+h/R)^2)rArr1/16g=g/((1+h/R)^2)`
`rArr1+h/R=4rArrh=3R`
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