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The imaginary angular velocity of the ea...

The imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero is equal to
[Take g `= 10 m//s^(2)` for the acceleration due to gravity if the earth were at rest and radius of earth equal to 6400 km.]

A

`1.25xx10^(-3)rad//s`

B

`2.50xx10^(-3)rad//s`

C

`3.75xx10^(-3)rad//s`

D

`5.0xx10^(-3)rad//s`

Text Solution

Verified by Experts

The correct Answer is:
A
`g.=g-omega^2Rcos^2lamda=0`
`omega^2R=g`
`rArromega=sqrt((9.8)/(6400xx10^3))`
`omega=1.25xx10^(-3)` rad/s
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