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A body of mass m kg starts falling from ...

A body of mass m kg starts falling from a point 2R above the earth's surface. Its kinetic energy when its has fallen to a point 'R' above the earth's surface [R-Radius of earth M-mass of earth, G-gravitational constant]

A

`1/2(GMm)/R`

B

`1/6(GMm)/R`

C

`2/3(GMm)/R`

D

`1/3(GMm)/R`

Text Solution

Verified by Experts

The correct Answer is:
B

Law of conservation of energy
`(-GMm)/(3R)=(-GMm)/(2R)+1/2mv^2rArr1/2mv^2=(GMm)/(6R)`
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