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For a gas molecule with 6 degrees of fre...

For a gas molecule with 6 degrees of freedom,the law of equipartion of energy gives the following relation between the molecular specific heat `(C_(V))` and gas constant (R)

A

`C_v=R/2`

B

`C_V=R`

C

`C_V=2R`

D

`C_v=3R`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_V=f/2 R=6/2 R =3R`
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