The temperature of the mixture of one mole of helium and one mole of hydrogen is increased from 0°C to 100°C at constant pressure. The amount of heat delivered will be

Options

A. 600 cal
B. 1200 cal
C. 1800 cal
D. 3600 cal

Answer

B

Explanation

`(C_p)_("mix")=(n_1C_(p_1)+n_2C_(p_2))/(n_1+n_2)`
`=(1xx5/2 R +1 xx 7/2 R)/(1+1)=3R=6 cal//mol^(-1)k^(-1)`
Heat `(DeltaQ)_P=nC_P DeltaT=2xx6xx100=1200` cal.