Arrange the following steps of construction of a `DeltaABC` whose base BC = 5.6 cm, `angleB = 45^(@)` and AC – AB = 1.6 cm in correct sequence.
Steps of Construction :
Step 1: Join CD.
Step 2 : Draw the perpendicular bisector of CD which cuts BX at A.
Step 3 : Join AC to obtain the required `DeltaABC`.
Step 4 : Draw `angleCBX = 45^(@)`
Step 5: From ray BX, cut offline segment BD = 1.6 cm = AC – AB
Step 6 : Draw base BC = 5.6 cm.

Options

A. 1, 2, 3, 5, 6, 4
B. 6, 4, 2, 5, 1, 3
C. 6,4,5, 1, 2, 3
D. 6, 1, 5, 2, 4,3

Answer

To construct triangle \( \Delta ABC \) with the given conditions, we need to arrange the steps in the correct sequence. Here’s the step-by-step solution:

### Step-by-Step Solution:

1. **Step 6: Draw base BC = 5.6 cm.**
- Start by drawing a line segment BC that measures 5.6 cm.

2. **Step 4: Draw angle CBX = 45°.**
- At point B, use a protractor to measure and draw an angle of 45° with ray BX extending from point B.

3. **Step 5: From ray BX, cut off line segment BD = 1.6 cm.**
- Measure 1.6 cm along ray BX from point B and mark this point as D.

4. **Step 1: Join CD.**
- Now, draw a line segment connecting points C and D.

5. **Step 2: Draw the perpendicular bisector of CD which cuts BX at A.**
- Find the midpoint of segment CD and draw the perpendicular bisector of CD. This line will intersect ray BX at point A.

6. **Step 3: Join AC to obtain the required triangle \( \Delta ABC \).**
- Finally, draw line segment AC to complete triangle \( \Delta ABC \).

### Final Sequence of Steps:
1. Step 6
2. Step 4
3. Step 5
4. Step 1
5. Step 2
6. Step 3