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The electronic configuration of four ele...

The electronic configuration of four elements are :
(P) `[Xe]6s^(2)`
(Q) `[Xe]4f^(14),5d^(1),6s^(2)`
(R) `[Ar]4s^(2),4p^(5)`
(S) `[Ar]3d^(10),4s^(2),4p^(3)`
Which of the following is/are correct?

A

1 is a strong reducing agent

B

2 is a d–block element

C

3 has high electron affinity

D

4 shows variable oxidation state

Text Solution

Verified by Experts

The correct Answer is:
B
`[Xe] 4f^14 5d^1 6s^2` is the electronic configration of Lutetium which is f - block element.
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