The correct order of increasing radii of the ions `Br^(-), F^(-), O^(2-) and S^(2-)` is as follows

Options

A. `Br^(-) lt F^(-) lt O^(2-) lt S^(2-)`
B. `S^(2-) lt O^(2-) lt F^(-) lt Br^(-)`
C. `F^(-) lt O^(2-) lt S^(2-) lt Br^(-)`
D. `F^(-) lt Br^(-) lt O^(2-) lt S^(2-)`

Answer

C

Explanation

`F^(-) and O^(2-)` are isoelectronic but nuclear charge of `F^(-) gt O^2`. Hence, ionic radius of `F^(-) lt O^(2-)`. So the order is `F^(-) lt O^(2-) lt S^(2-) lt Br^(-)`.