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4.48 L of an ideal gas at STP requires 1...

`4.48 L` of an ideal gas at `STP` requires 12 cal to raise its temperature by `15^(@)C` at constant volume. The `C_(P)` of the gas is

A

3 cal

B

4 cal

C

7 cal

D

6 cal

Text Solution

Verified by Experts

The correct Answer is:
D

No. of moles of ideal gas at STP ` = (4.48)/(22.4) ` = 0.2 mol
`Delta U = Delta n C_v Delta T, 12 = (4.48)/(22.4) xx C_v xx 15, 12 = 0.2 xx C_v xx 15`,
`therefore C_v = 12//3 = 4, C_p - C_v = R ~~2,`
`therefore Cp = 2 + C_v = 2+4 ~~ 6 "cal mol"^(-1)`
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