For the reaction:
`X_(2)O_(4)(l)rarr2XO_(2)(g)`
`DeltaU=2.1 cal , DeltaS =20 "cal" K^(-1) "at" 300 K`
Hence `DeltaG` is

Options

A. 9.3 kcal
B. `-9.3` kcal
C. 2.7 kcal
D. `-2.7` kcal

Answer

D

Explanation

`X_(2)O_(4) (l) rarr 2XO_(2)(g)`
`Delta n_(g)= 2- 0= 2`
`Delta H= Delta U + Delta n_(g) RT`
`Delta G= Delta H- T Delta S`
= 2.1 kcal `+ (2 xx 2 xx 10^(-3) xx 300) - (300 xx 20) kcal xx 10^(-3)= -2.7 kcal`