How much of NaOH is reuired to neutralise 1500 `cm^(3)` of 0.1 N HCl (Na=23)?

Options

A. 40g
B. 4g
C. 6g
D. 60g

Answer

C

Explanation

`N = (W(g) xx 1000)/(V xx Eq.wt)`
1500mL of 0.1NHCl =150mL (N)
` 1 = (W(g) xx 1000)/(150 xx 40) ,W(g) = (150 xx 40)/(1000) = 6g`