Number of hydrogen ions present in 10 millionth part of `1.33 cm^(3)` of pure water at `25^(@)C` is

Options

A. 6.023 million
B. 60 million
C. 8.01 million
D. 80.23 million

Answer

C

Explanation

A mole contains `6.022 xx 10^(23)` ions
Concentration of free `H^(+)` ions.
Volume of water `= (1.33)/(10^(3)) L xx (1)/(10000000)`
So.no. of hydrogen ions ` = (1.33)/(10^(3) xx 10^(7)) xx 6.022 xx 10^(23) xx 10^(-7)`
= 8.01 million.