The decomposition of cetian mass of `CaCO_(3)` gave `11.2dm^(3)` of `CO_(2)` gas at STP. The mass of KOH required to completely neutralise the gas is:

Options

A. 56 g
B. 28 g
C. 42 g
D. 20 g

Answer

B

Explanation

Weight of `11.2 dm^(3)` of `CO_(2)` gas at STP is 44/2 = 22 g
`underset(56 g)(KOH) + underset(44g)(CO_(2)) to KHCO_(3)`
KOH required for complete neutralisation of 22 g `CO_(2)` is `(56)/(44) xx 22 = 28 g`