1 g of a mixture of `NaHCO_(3)` and `Na_(2)CO_(3)` is heated to `150^(@)C`. The volume of the `CO_(2)` produced at STP is 112.0 mL. Calculate the percentage of `Na_(2)CO_(3)` in the mixture `(Na=23, C=12, O=16)`

Options

A. 20
B. 46
C. 84
D. 16

Answer

D

Explanation

`2NaHCO_(3) overset(150^(@)C) to Na_(2)CO_(3) + CO_(2) + H_(2)O`
`(n_(NaHCO_(3)))/(N_(CO_(2))) = (2)/(1) rArr n_(NaHCO_(3)) =2n_(CO_(2)) = 2 xx (112)/(22400) =0.01` mole
`W_(NaHCO_(3)) =0.01 xx 84 = 0.84g`
`W_(Na_(2)CO_(2)) = 1.00 - 0.84 = 0.16 g`
`%Na_(2)CO_(3) = 16`