By dissolving 35 .0 mole of sodium chloride in water, L30.1 of salt solution is obtained. The molarity of the resulting solution should be reported as

Options

A. 0.3
B. 0.269
C. 0.27
D. 0.2692

Explanation

To find the molarity of the sodium chloride solution, we can follow these steps:

### Step 1: Identify the number of moles of solute
We are given that there are 35.0 moles of sodium chloride (NaCl).

### Step 2: Identify the volume of the solution
The volume of the salt solution is given as 1.30 liters.

### Step 3: Use the molarity formula
Molarity (M) is defined as the number of moles of solute divided by the volume of the solution in liters. The formula is:

\[ \text{Molarity (M)} = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \]

### Step 4: Substitute the values into the formula
Now we can substitute the values we have into the formula:

\[ \text{Molarity (M)} = \frac{35.0 \, \text{moles}}{1.30 \, \text{liters}} \]

### Step 5: Calculate the molarity
Now we perform the calculation:

\[ \text{Molarity (M)} = \frac{35.0}{1.30} \approx 26.92 \, \text{M} \]

### Step 6: Report the final answer
The molarity of the resulting sodium chloride solution is approximately 26.92 M.

---