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An element X has the following isotopic ...

An element X has the following isotopic composition:
`""^(200)X:90% ""^(199)X:8.0% ""^(202)X:2.0%`
The weight average atomic mass of the naturally occurring element X is closest to

A

200 amu

B

201 amu

C

202 amu

D

199 amu

Text Solution

Verified by Experts

The correct Answer is:
C
Avg. atomic mass ` = (200 xx 90 + 199 xx 8+302 xx 2)/(100)`
`201.96 ~=202`
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