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The equivalent weight of phosphoric acid...

The equivalent weight of phosphoric acid `(H_(3)PO_(4))` in the reaction `NaOH+H_(3)PO_(4) rarr NaH_(2)PO_(4)+H_(2)O` is

A

25

B

49

C

59

D

98

Text Solution

Verified by Experts

The correct Answer is:
D
`NaOH + underset((PO_(4)^(-3)))(H_(2)PO_(4)) to underset((NaPO_(4)^(-2)))(NaH_(2)PO_(4))`
`EW = (MV)/("No.of ionisable" H^(+)) = (98)/(1)`
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