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A mixture of 2.3 g formic acid and 4.5 g...

A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. `H_(2)SO_(4)`. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be

A

1.4

B

3

C

2.8

D

4.4

Text Solution

Verified by Experts

The correct Answer is:
C

`underset("Formic acid")(H-overset(O)overset(||)(C) - OH) to H_(2)O + CO`
`underset("Oxalic acid")(HO - overset(O)overset(||)(C)- overset(O)overset(||)(C)- OH) overset(H_(2)SO_(4)) to H_(2)O + CO_(2) + CO`
46g of `H - overset(O)overset(||)(C)- overset(O)overset(||)(C) - OH rArr28g` of CO
`therefore` 2.3 g `HCOOH rArr = 1.4g `CO
90g. of oxalic acid `rArr` = 28 g CO
`therefore ` 4.5g oxalic acid `rArr` 1.4 g CO
Total is 2.8g CO
[`H_(2)O` will be absorbed by `H_(2)SO_(4)` and `CO_(2)` will be absorbed by KOH].
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