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The bond order of which of the following...

The bond order of which of the following molecules/ ion(s) is 3

A

`O_2 and NO^(+)`

B

`N_2 and NO^(+)`

C

`N_2 and NO`

D

`N_2^(+) and NO^(+)`

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The correct Answer is:
To determine the bond order of the given molecules or ions and identify which has a bond order of 3, we can follow these steps: ### Step 1: Understand Bond Order Bond order is defined as the number of bonds between two atoms. It can be calculated using the formula: \[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \] where \( N_b \) is the number of bonding electrons and \( N_a \) is the number of antibonding electrons. ### Step 2: Identify the Molecules/Ions We need to analyze the following species: 1. O2 2. NO+ 3. N2 4. N2+ ### Step 3: Calculate the Total Electrons for Each Species - **O2**: Oxygen has 8 electrons, so O2 has \( 8 + 8 = 16 \) electrons. - **NO+**: Nitrogen has 7 electrons and Oxygen has 8. Therefore, NO+ has \( 7 + 8 - 1 = 14 \) electrons (subtracting one for the positive charge). - **N2**: Each nitrogen has 7 electrons, so N2 has \( 7 + 7 = 14 \) electrons. - **N2+**: N2 has 14 electrons, and removing one for the positive charge gives \( 14 - 1 = 13 \) electrons. ### Step 4: Determine Isoelectronic Species Species that have the same number of electrons are called isoelectronic. In this case: - O2 (16 electrons) - NO+ (14 electrons) - N2 (14 electrons) - N2+ (13 electrons) ### Step 5: Calculate Bond Order for Each Species - **For N2**: - Bonding electrons = 10, Antibonding electrons = 0 - Bond Order = \( \frac{(10 - 0)}{2} = 5 \) - **For NO+**: - Bonding electrons = 10, Antibonding electrons = 1 - Bond Order = \( \frac{(10 - 1)}{2} = 4.5 \) - **For O2**: - Bonding electrons = 10, Antibonding electrons = 6 - Bond Order = \( \frac{(10 - 6)}{2} = 2 \) - **For N2+**: - Bonding electrons = 9, Antibonding electrons = 1 - Bond Order = \( \frac{(9 - 1)}{2} = 4 \) ### Step 6: Identify the Species with Bond Order of 3 From the calculations: - N2 has a bond order of 3. - NO+ has a bond order of 4.5. - O2 has a bond order of 2. - N2+ has a bond order of 4. Thus, the only species with a bond order of 3 is **N2**. ### Final Answer The bond order of **N2** is 3. ---

To determine the bond order of the given molecules or ions and identify which has a bond order of 3, we can follow these steps: ### Step 1: Understand Bond Order Bond order is defined as the number of bonds between two atoms. It can be calculated using the formula: \[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \] where \( N_b \) is the number of bonding electrons and \( N_a \) is the number of antibonding electrons. ### Step 2: Identify the Molecules/Ions ...
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ERRORLESS-CHEMICAL BONDING AND MOLECULAR STRUCTURE-NCERT BASED QUESTIONS (Molecular Orbital Theory)
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  2. The pair of species with the same bond order is :

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  3. The bond order of which of the following molecules/ ion(s) is 3

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  4. Bond order and magnetic moment of CO^+ is

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  5. The correct statement with regard to H2^(+) and H2^(-) is

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  6. Bond order of O2,O2^(2-),O2^-,O2^+

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  7. If bond order increase than .

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  8. The bond order of the N-O bonds in NO3^- ion is

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  9. Assuming that Hund's rule is violated the bond order and magnetic natu...

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  10. The paramagnetic behaviour of B2 is due to the presence of

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  11. Which one is paramagnetic from the following

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  12. Which of the following molecule is paramagnetic

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  13. Which one of the following sepcies is diamagnetic in nature ?

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  14. According to molecular orbital theory, the paramagnetism of O(2) molec...

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  15. Which of the following is paramagnetic

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  16. Which of the following molecules/ins does not contain unpaired electro...

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  17. Using MOT, compare O2^(+) and O2^(-) species and choose the incorrect ...

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  18. Which one of the following oxides is expected to exhibit paramagnetic ...

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  19. N2 and O2 are converted into monoanions N2^- and O2^- respectively. Wh...

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  20. Which one does not exhibit paramagnetism

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