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The diamagnetic species is...

The diamagnetic species is

A

NO

B

`NO_2`

C

`O_2`

D

`CO_2`

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The correct Answer is:
To determine which species is diamagnetic, we need to analyze the electronic configurations of the given species. A diamagnetic species is one that has all its electrons paired, resulting in no net magnetic moment. Here’s a step-by-step solution: ### Step 1: Identify the species and their electron counts We need to consider the electron configurations of the given species. The question does not specify which species to analyze, so we will assume common examples such as O2, NO, NO2, and CO2 based on the transcript. ### Step 2: Count the total number of electrons for each species 1. **O2 (Oxygen)**: Each oxygen atom has 8 electrons, so O2 has 16 electrons (8 + 8). 2. **NO (Nitric Oxide)**: Nitrogen has 7 electrons and oxygen has 8 electrons, so NO has 15 electrons (7 + 8). 3. **NO2 (Nitrogen Dioxide)**: Nitrogen has 7 electrons and each oxygen has 8 electrons, giving NO2 a total of 23 electrons (7 + 8 + 8). 4. **CO2 (Carbon Dioxide)**: Carbon has 6 electrons and each oxygen has 8 electrons, resulting in CO2 having 22 electrons (6 + 8 + 8). ### Step 3: Analyze the electron pairing - **O2**: Despite having an even number of electrons (16), it has unpaired electrons in its molecular orbital configuration, making it paramagnetic. - **NO**: With 15 electrons, it has unpaired electrons, making it paramagnetic. - **NO2**: With 23 electrons, it also has unpaired electrons, making it paramagnetic. - **CO2**: With 22 electrons, all electrons are paired, making it diamagnetic. ### Step 4: Conclusion From the analysis, CO2 is the only species that is diamagnetic because it has all its electrons paired. ### Final Answer The diamagnetic species is **CO2**. ---

To determine which species is diamagnetic, we need to analyze the electronic configurations of the given species. A diamagnetic species is one that has all its electrons paired, resulting in no net magnetic moment. Here’s a step-by-step solution: ### Step 1: Identify the species and their electron counts We need to consider the electron configurations of the given species. The question does not specify which species to analyze, so we will assume common examples such as O2, NO, NO2, and CO2 based on the transcript. ### Step 2: Count the total number of electrons for each species 1. **O2 (Oxygen)**: Each oxygen atom has 8 electrons, so O2 has 16 electrons (8 + 8). 2. **NO (Nitric Oxide)**: Nitrogen has 7 electrons and oxygen has 8 electrons, so NO has 15 electrons (7 + 8). ...
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ERRORLESS-CHEMICAL BONDING AND MOLECULAR STRUCTURE-NCERT BASED QUESTIONS (Molecular Orbital Theory)
  1. According to molecular orbital theory, the paramagnetism of O(2) molec...

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  2. Which of the following is paramagnetic

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  3. Which of the following molecules/ins does not contain unpaired electro...

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  4. Using MOT, compare O2^(+) and O2^(-) species and choose the incorrect ...

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  5. Which one of the following oxides is expected to exhibit paramagnetic ...

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  6. N2 and O2 are converted into monoanions N2^- and O2^- respectively. Wh...

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  7. Which one does not exhibit paramagnetism

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  8. Substance which is weakly repelled by a magnetic field is

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  9. Bond energies in NO,NO^(+) and NO^(-) are such as

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  10. Which of the following order of energies of moleuclar orbitals of N...

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  11. Which of the following statement is not correct from the view point of...

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  12. Arrange the following ions in the order of decreasing X-O bond length ...

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  13. The correct order of O-O bond length in O2,H2 O and O3.

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  14. The correct order of increasing C - O bond length CO, CO3^(2-) , CO2 i...

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  15. The bond order of super oxide ion O2^(2-) is

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  16. Among the following, the species with the highest bond order is-

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  17. The correct order of increasing C-O bond lengths in CO, CO3^(2-) and ...

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  18. The diamagnetic species is

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  19. In which of the following processes, the bond order has increased and ...

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  20. During the change of O(2) to O(2)^(-), the incoming electron goes to t...

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