The freezing points of equimolar solutions of glucose `KNO_(3) and AlCl_(3)` are in order of _____.

Options

A. `AlCl_(3)ltKNO_(3)lt`Glucose
B. Glucose`ltKNO_(3)ltAlCl_(3)`
C. Glucose`ltAlCl_(3)ltKNO_(3)`
D. `AlCl_(3)lt`Glucose`ltKNO_(3)`

Answer

A

Explanation

The value of i for glucose, `KNO_(3)` and `AlCl_(3)` are 1, 2 and 4 respectively so the depression in freezing point will be in the order of `AlCl_(3)gtKNO_(3)gt` Glucose. Hence the freezing points of equimolar solutions will be in the order of `AlCl_(3)ltKNO_(3)lt` Glucose.