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We have three aqueous solutions of NaCl ...

We have three aqueous solutions of NaCl labelled as A, B and C with concentration `0.1 M , 0.01 "and" 0.001` M , respectively . The value of van't Hoff factor for these solutions will be in the order :

A

`i_(A)lti_(B)lti_(C)`

B

`i_(A)gti_(B)gti_(C)`

C

`i_(A)=i_(B)=i_(C)`

D

`i_(A)lti_(B)gti_(C)`

Text Solution

Verified by Experts

The correct Answer is:
A
Van’t Hoff’s factor i depends on the degree of dissociation `(alpha)` and the value of `alpha` increases with the increase of dilution of an electrolyte solution
So `alpha_(A)ltalpha_(B)ltalpha_(C)`
or `i_(A)lti_(B)lti_(C)`.
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