The compound `(CH_3)_2.overset(OH)overset(|)("CCCl"_3)` is

Options

A. Chloretone
B. Chloroquin
C. Chloropicrin
D. Chloropropyl chloride

Explanation

To determine the compound `(CH_3)_2C(OH)(CCl_3)`, we will analyze its structure step by step.

### Step 1: Identify the structure
The given compound can be broken down as follows:
- `(CH_3)_2` indicates two methyl groups (−CH₃).
- `C(OH)` indicates a carbon atom bonded to a hydroxyl group (−OH).
- `(CCl_3)` indicates a carbon atom bonded to three chlorine atoms (−CCl₃).

### Step 2: Construct the molecular structure
From the breakdown:
1. Start with a central carbon atom (C) that is connected to:
- Two methyl groups (−CH₃).
- One hydroxyl group (−OH).
- One carbon atom that is connected to three chlorine atoms (−CCl₃).

The structure can be represented as:
```
CH3
|
CH3 - C - OH
|
CCl3
```

### Step 3: Determine the IUPAC name
To name the compound, we need to identify the longest carbon chain and the functional groups:
1. The central carbon is a tertiary carbon because it is attached to three other carbon atoms.
2. The presence of the hydroxyl group (−OH) indicates that this is an alcohol.
3. The compound has a total of four carbon atoms, and the presence of three chlorine atoms suggests it is a haloalkane as well.

The IUPAC name for this compound is **2-chloro-2-methylpropan-1-ol**.

### Final Answer
The compound `(CH_3)_2C(OH)(CCl_3)` is **2-chloro-2-methylpropan-1-ol**.

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