Which of the following intermediates is pyramidal in shape

Options

A. `H_(3) C^(oplus)`
B. `H_(2) overset(..) ( C)`
C. `H_(3) C :^(Theta)`
D. `HC -= C :^(Theta)`

Explanation

To determine which of the following intermediates is pyramidal in shape, we need to analyze the molecular geometry of the given intermediates. The pyramidal shape typically refers to a molecular geometry where a central atom is bonded to three other atoms and has a lone pair of electrons, resulting in a trigonal pyramidal shape.

### Step-by-Step Solution:

1. **Identify the Intermediates**:
- Let's consider common intermediates such as CH3⁻ (methyl anion), NH3 (ammonia), and others that might be provided in the question.

2. **Analyze CH3⁻ (Methyl Anion)**:
- The methyl anion (CH3⁻) has a central carbon atom bonded to three hydrogen atoms and carries a negative charge.
- The carbon atom has no lone pairs, and thus the geometry is tetrahedral, not pyramidal.

3. **Analyze NH3 (Ammonia)**:
- Ammonia (NH3) has a nitrogen atom bonded to three hydrogen atoms and has one lone pair of electrons.
- The presence of the lone pair causes the molecule to adopt a trigonal pyramidal shape.

4. **Consider Other Intermediates**:
- If there are other intermediates provided in the question, analyze their structures similarly, looking for lone pairs and the number of bonds.

5. **Conclusion**:
- Among the intermediates analyzed, NH3 is the one that is pyramidal in shape due to the presence of a lone pair on nitrogen.

### Final Answer:
The intermediate that is pyramidal in shape is **NH3 (Ammonia)**.