Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative ?

Options

A. `CH_(3) - CH_(2) -^(**)CH_(2) - CH_(3)`
B. `CH_(3) -^(**)CH = CH - CH_(3)`
C. `CH_(3) - CH_(2)-C=^(**)CH`
D. `CH_(3) - CH_(2) - CH =^(**)CH_(2)`

Answer

C

Explanation

Electronegativity of carbon atom depends on their state of hybridisation. More s-character more the electronegativity.
`sp^(3) lt sp^(2) lt sp`
`25 % s 33% s 50 % s`
Thus sp- carbon has the highest electronegativity i.e., option ( c) `(CH_(3) - CH_(2) - C -= ""^(**) CH)` is correct