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In the following compound, the number of...

In the following compound, the number of ‘sp’ hybridized carbon is
`CH_(2)= C = CH - underset(CN)underset(|)( C)H - C-= CH`

A

2

B

3

C

4

D

5

Text Solution

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The correct Answer is:
To determine the number of 'sp' hybridized carbon atoms in the compound `CH2=C=CH-C≡C-CN`, we will analyze the structure step by step. ### Step 1: Identify the Structure The compound can be represented as follows: - **CH2** (first carbon) - **C** (second carbon, part of a double bond) - **C** (third carbon, part of a double bond) - **C** (fourth carbon, part of a triple bond with nitrogen) - **C** (fifth carbon, part of a triple bond) - **N** (attached to the fourth carbon) ### Step 2: Determine Hybridization of Each Carbon 1. **First Carbon (CH2)**: - Forms 2 sigma bonds (with 2 H atoms). - Hybridization: **sp²** (since it has 3 regions of electron density: 2 sigma bonds + 1 double bond). 2. **Second Carbon (C)**: - Forms 1 sigma bond (with the first carbon) and 1 pi bond (with the third carbon). - Hybridization: **sp** (since it has 2 regions of electron density: 1 sigma bond + 1 pi bond). 3. **Third Carbon (C)**: - Forms 1 sigma bond (with the second carbon) and 1 pi bond (with the fourth carbon). - Hybridization: **sp** (since it has 2 regions of electron density: 1 sigma bond + 1 pi bond). 4. **Fourth Carbon (C)**: - Forms 1 sigma bond (with the third carbon) and 2 pi bonds (with the nitrogen). - Hybridization: **sp** (since it has 2 regions of electron density: 1 sigma bond + 2 pi bonds). 5. **Fifth Carbon (C)**: - Forms 1 sigma bond (with the fourth carbon) and 1 sigma bond (with the nitrogen). - Hybridization: **sp** (since it has 2 regions of electron density: 1 sigma bond + 1 sigma bond). ### Step 3: Count the 'sp' Hybridized Carbons From the analysis: - The second carbon is **sp** hybridized. - The third carbon is **sp** hybridized. - The fourth carbon is **sp** hybridized. - The fifth carbon is **sp** hybridized. ### Conclusion Total number of 'sp' hybridized carbon atoms = **4**. ### Final Answer The number of ‘sp’ hybridized carbon atoms in the compound is **4**. ---
To determine the number of 'sp' hybridized carbon atoms in the compound `CH2=C=CH-C≡C-CN`, we will analyze the structure step by step. ### Step 1: Identify the Structure The compound can be represented as follows: - **CH2** (first carbon) - **C** (second carbon, part of a double bond) - **C** (third carbon, part of a double bond) - **C** (fourth carbon, part of a triple bond with nitrogen) ...
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In the following compound, the number of 'sp' hybridised carbon is: H_(2)C=C=CH-underset(CN)underset(|)(CH)-C-=CH

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