If `veca = 2hati - hatj + hatk, vecb = hati + hatj - 2hatk` and `vecc = hati + 3hatj - hatk` and the projection of vectorc `vecc + lambdavecb` on vector `veca` is `2sqrt(6)`, then find the value of `lambda`.

If veca = 2 hati - 3hatj, vecb = hati + hatj -hatk, vecc = 3hati - hatk, find [a vecb vecc]

If veca =hati + hatj-hatk, vecb = - hati + 2hatj + 2hatk and vecc = - hati +2hatj -hatk , then a unit vector normal to the vectors veca + vecb and vecb -vecc , is

Given : vecA = 2hati - hatj + 2hatk and vecB = -hati - hatj + hatk . The unit vector of vecA - vecB is

If vecA=2hati+3hatj-hatk and vecB=-hati+3hatj+4hatk then projection of vecA on vecB will be

If veca=3hati+hatj-4hatk and vecb=6hati+5hatj-2hatk find |veca Xvecb|

Find vecB xx vecA if vecA = 3hati - 2hatj + 6hatk and vecB = hati - hatj + hatk .

Let veca= 2 hati + 3hatj - 6hatk, vecb = 2hati - 3hatj + 6hatk and vecc = -2 hati + 3hatj + 6hatk . Let veca_(1) be the projection of veca on vecb and veca_(2) be the projection of veca on vecc . Then which of the following is true ?

If veca=2hati+3hatj+hatk, vecb=hati-2hatj+hatk and vecc=-3hati+hatj+2hatk , then [veca vecb vecc]=

Let veca=hati-hatj+hatk, vecb=2hati+hatj+hatk and vecc=hati+hatj-2hatk , then the value of [(veca, vecb, vecc)] is equal to

Let veca=hati + hatj +hatk,vecb=hati- hatj + hatk and vecc= hati-hatj - hatk be three vectors. A vectors vecv in the plane of veca and vecb , whose projection on vecc is 1/sqrt3 is given by