The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be __________J. (Given R= 8.31 J/mol.K)

Internal energy of an ideal diatomic gas at 300 K is 100 J. In this 100 J

Total random kinetic energy of the molecules in 1 mole of a gas at a temperature of 300 K is (R = 2 cal/mole °C)

Internal energy of n moles of helium at temperature T_1 K is equal to the internal energy of 2n moles of oxygen gas at temperature T_2 K then the value of T_1 /T_2 will be

The kinetic energy of one g-mole of a gas at normal temp erature and pressure is its thennal motion? [AIEEE 2009} (R == 8.31 J/mole -K)

Two moles of ideal helium gas are in a rubber balloon at 30^@C. The balloon is fully expandable and can be assumed to require no energy in its expansion. The temperature of the gas in the balloon is slowly changed to 35^@C. The amount of heat required in raising the temperature is nearly (take R =8.31 J//mol.K )

The kinetic energy of one gram molecule of a gas at normal temperature and pressure is (R=8.31J//mol-K)

The ratio of translational and rotational kinetic energies at 100K temperature is 3:2 . Then the internal energy of one mole gas at that temperature is (R=8.3j//"mol"-K]