White precipitate of AgCl dissolves in aqueous ammonia solution due to formation of :

Options

A. `[Ag(NH_(3))_(4)]Cl_(2)`
B. `[Ag(Cl)_(2)(NH_(3))_(2)]`
C. `[Ag(NH_(3))_(2)]Cl`
D. `[Ag(NH_(3))Cl]Cl`

Explanation

To solve the question regarding the dissolution of white precipitate AgCl in aqueous ammonia, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the White Precipitate**:
The white precipitate in question is Silver Chloride (AgCl).

2. **Understand the Reaction with Ammonia**:
When AgCl is treated with aqueous ammonia (NH₃), it can dissolve due to the formation of a complex ion.

3. **Write the Reaction**:
The reaction can be represented as:
\[ \text{AgCl (s)} + 2 \text{NH}_3 (aq) \rightarrow \text{[Ag(NH}_3\text{)}_2]^+ (aq) + \text{Cl}^- (aq) \]
Here, the silver ion (Ag⁺) forms a complex with ammonia, resulting in the complex ion \([Ag(NH_3)_2]^+\).

4. **Identify the Complex Ion**:
The complex formed is \([Ag(NH_3)_2]^+\), which is soluble in water, hence the AgCl precipitate dissolves.

5. **Select the Correct Option**:
From the options provided, the correct answer is the one that represents the complex ion formed, which is \([Ag(NH_3)_2]^+\) along with the chloride ion (Cl⁻).

### Conclusion:
The white precipitate of AgCl dissolves in aqueous ammonia due to the formation of the complex ion \([Ag(NH_3)_2]^+\).