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The major product in the reaction CH(3) ...

The major product in the reaction `CH_(3) -overset (CH_(3)) overset (|) underset (CH_(3)) underset (|)C-Cl +overset (+)(K)overset (-)O-overset (CH_(3)) overset (|) underset (CH_(3)) underset (|)C-CH_(3) to ` ? Is

A

t- Butyl ethyl ether

B

2,2- Dimethyl butane

C

2-methyl pent -1-ene

D

2-Methyl prop -1-ene

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The correct Answer is:
To find the major product of the given reaction, we can follow these steps: ### Step 1: Identify the Reactants We have a tertiary alkyl halide (specifically, a tertiary chloride) and a strong base, which is potassium tert-butoxide (KOC(CH₃)₃). ### Step 2: Determine the Mechanism Given that we have a tertiary alkyl halide and a strong base, the reaction will likely proceed via the E2 elimination mechanism. In this mechanism, the base abstracts a proton from the β-carbon while the leaving group (Cl) departs simultaneously. ### Step 3: Identify the β-Hydrogens In the structure of the tertiary alkyl halide, we need to identify the β-hydrogens. The β-carbon is the carbon adjacent to the carbon bonded to the chlorine. In this case, we have multiple β-hydrogens available for abstraction. ### Step 4: Base Abstraction The strong base (potassium tert-butoxide) will abstract one of the β-hydrogens. The choice of which β-hydrogen to abstract can influence the product, but in this case, we will consider the most accessible β-hydrogen. ### Step 5: Formation of the Alkene As the base abstracts the β-hydrogen, the bond between the β-carbon and the hydrogen will break, and the bond between the α-carbon (the carbon attached to the chlorine) and the chlorine will also break, resulting in the formation of a double bond between the α and β-carbons. ### Step 6: Naming the Product After the elimination reaction, we will have an alkene. The product will be a substituted alkene. We can name the product based on the position of the double bond and the substituents: - The product formed will be 2-methylpropene (or 2-methylprop-1-ene). ### Final Product The major product of the reaction is **2-methylpropene**. ---

To find the major product of the given reaction, we can follow these steps: ### Step 1: Identify the Reactants We have a tertiary alkyl halide (specifically, a tertiary chloride) and a strong base, which is potassium tert-butoxide (KOC(CH₃)₃). ### Step 2: Determine the Mechanism Given that we have a tertiary alkyl halide and a strong base, the reaction will likely proceed via the E2 elimination mechanism. In this mechanism, the base abstracts a proton from the β-carbon while the leaving group (Cl) departs simultaneously. ...
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