What will be the most suitable combination of three resistors`A = 2Omega, B=4 Omega, C = 6 Omega,` so that `(22/3) Omega` is equivalent resistance of combination?

Options

A. Parallel combination of A and C connected in series with B
B. Parallel combination of A and B connected in series with C
C. Rec Series combination of A and C connected in parallel with B.
D. Series combination of B and C connected in parallel with A

Explanation

To find the most suitable combination of the resistors A (2Ω), B (4Ω), and C (6Ω) to achieve an equivalent resistance of \( \frac{22}{3} \)Ω, we will explore different combinations of series and parallel connections.

### Step-by-Step Solution:

1. **Understanding the Problem**:
We need to find a combination of the resistors such that the total equivalent resistance is \( \frac{22}{3} \)Ω.

2. **Option 1: Parallel Combination of A and C, in Series with B**:
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