The light of two different frequencies whose photons have energies 3.8 eV and 1.4 eV respectively, illuminate a metallic surface whose work function is 0.6 eV successively. The ratio of maximum speeds of emitted electrons for the two frequencies respectivly will be-

Options

A. `1:1`
B. `2:1`
C. `4:1`
D. `1:4`

Explanation

To solve the problem, we will use the photoelectric effect equation, which relates the energy of the incoming photons to the work function of the material and the kinetic energy of the emitted electrons.

### Step-by-Step Solution:

1. **Identify the energies of the photons and the work function**:
- Energy of the first photon, \( E_1 = 3.8 \, \text{eV} \)
- Energy of the second photon, \( E_2 = 1.4 \, \text{eV} \)
- Work function of the metallic surface, \( \phi = 0.6 \, \text{eV} \)
...