A ray of light is incident at an angle of incidence `60^(@)` on the glass slab of refractive index `sqrt3`. After refraction, the light ray emerges out from other parallel faces and lateral shift between incident ray and emergent ray is `4sqrt(3)` cm. The thickness of the glass slab is _____cm.

Explanation

To solve the problem, we need to find the thickness of a glass slab given the angle of incidence, the refractive index, and the lateral shift of the emergent ray.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Angle of incidence, \( i = 60^\circ \)
- Refractive index of glass, \( \mu = \sqrt{3} \)
- Lateral shift, \( d = 4\sqrt{3} \) cm
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