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The gas produced by treating an aqueous ...

The gas produced by treating an aqueous solution of ammonium chloride with
Question : sodium nitrite is

A

`NH_3`

B

`N_2`

C

`N_2O`

D

`Cl_2`

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The correct Answer is:
To solve the problem of identifying the gas produced by treating an aqueous solution of ammonium chloride (NH4Cl) with sodium nitrite (NaNO2), we can follow these steps: ### Step 1: Write the Reaction When ammonium chloride reacts with sodium nitrite, the chemical reaction can be written as follows: \[ \text{NH}_4\text{Cl} + \text{NaNO}_2 \rightarrow \text{NaCl} + \text{NH}_4\text{NO}_2 \] ### Step 2: Identify the Products From the reaction, we can see that the products formed are sodium chloride (NaCl) and ammonium nitrite (NH4NO2). ### Step 3: Analyze Ammonium Nitrite Ammonium nitrite (NH4NO2) is known to be unstable. When it is heated or decomposed, it breaks down into nitrogen gas (N2) and water (H2O). The decomposition reaction can be represented as: \[ \text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2 \text{H}_2\text{O} \] ### Step 4: Identify the Gas Produced From the decomposition of ammonium nitrite, we can see that the main gas produced is nitrogen (N2). ### Conclusion Thus, the gas produced by treating an aqueous solution of ammonium chloride with sodium nitrite is nitrogen (N2). ### Final Answer The gas produced is nitrogen (N2). ---

To solve the problem of identifying the gas produced by treating an aqueous solution of ammonium chloride (NH4Cl) with sodium nitrite (NaNO2), we can follow these steps: ### Step 1: Write the Reaction When ammonium chloride reacts with sodium nitrite, the chemical reaction can be written as follows: \[ \text{NH}_4\text{Cl} + \text{NaNO}_2 \rightarrow \text{NaCl} + \text{NH}_4\text{NO}_2 \] ### Step 2: Identify the Products ...
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