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Decarboxylation of all six possible form...

Decarboxylation of all six possible forms of diaminobenzoic acids `C_6H_3(NH_2)_2COOH` yields three products A, B and C. Three acids give a product 'A' two acids gives a products 'B' and one acid give a product 'C' . The melting point of product 'C' is

A

`63^@C`

B

`90^@C`

C

`104^@C`

D

`142^@C`

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The correct Answer is:
To solve the problem of the decarboxylation of all six possible forms of diaminobenzoic acids (C₆H₃(NH₂)₂COOH), we will follow these steps: ### Step 1: Identify the Isomers There are six possible isomers of diaminobenzoic acid based on the positions of the amino (NH₂) groups and the carboxylic acid (COOH) group on the benzene ring. The possible isomers are: 1. 2,3-diaminobenzoic acid (ortho-ortho) 2. 2,4-diaminobenzoic acid (ortho-meta) 3. 2,5-diaminobenzoic acid (ortho-para) 4. 3,4-diaminobenzoic acid (meta-meta) 5. 3,5-diaminobenzoic acid (meta-para) 6. 4,5-diaminobenzoic acid (para-para) ### Step 2: Perform Decarboxylation Decarboxylation involves the removal of the carboxyl group (COOH) from the acids, leading to the formation of amines. - **Product A**: Three isomers yield the same product upon decarboxylation. These are likely the ortho and para isomers, which will yield the same amine structure. - **Product B**: Two isomers yield another product. These could be the meta isomers, which may also yield a similar amine structure. - **Product C**: One isomer yields a unique product. This is likely the isomer that has the NH₂ groups in a configuration that leads to a different amine upon decarboxylation. ### Step 3: Identify the Products - **Product A**: The product from three isomers (likely the ortho and para configurations) will be a symmetrical amine. - **Product B**: The product from two isomers (likely the meta configurations) will also be a symmetrical amine but different from Product A. - **Product C**: The unique product from one isomer will be an amine that has a different structure due to the specific arrangement of the NH₂ groups. ### Step 4: Determine the Melting Point of Product C From the information provided, we know that Product C has a melting point of 142 degrees Celsius. This is a characteristic property of this specific amine formed from the unique isomer. ### Final Answer The melting point of product C is **142 degrees Celsius**.

To solve the problem of the decarboxylation of all six possible forms of diaminobenzoic acids (C₆H₃(NH₂)₂COOH), we will follow these steps: ### Step 1: Identify the Isomers There are six possible isomers of diaminobenzoic acid based on the positions of the amino (NH₂) groups and the carboxylic acid (COOH) group on the benzene ring. The possible isomers are: 1. 2,3-diaminobenzoic acid (ortho-ortho) 2. 2,4-diaminobenzoic acid (ortho-meta) 3. 2,5-diaminobenzoic acid (ortho-para) 4. 3,4-diaminobenzoic acid (meta-meta) ...
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