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If the initial pressure of a gass is 0....


If the initial pressure of a gass is 0.03 atm, the mass of the gas adsorbed per gram of the adsorbent is _____________ xx `10^(-2) g `

Text Solution

Verified by Experts

The correct Answer is:
12
`(x/m) = KP^(1//n)`
`log (x/m) = log K + 1/n log P`
Intercept log K = 0.602 = log 4
K= 4
Slope implies `1/n = 1 " " ` so `" " n = 1 `
so `(x/m) = 4(0.03) = 0.12 = 12 xx 10^(-2)`
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