Home
Class 12
BIOLOGY
How is Hardy-Weinberg's expression “(p^2...

How is Hardy-Weinberg's expression `“(p^2 + 2pq+q^2) = 1”` derived?

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER 2023 TERM I

    CBSE MODEL PAPER|Exercise SECTION - D|8 Videos
  • SAMPLE PAPER 2023 TERM I

    CBSE MODEL PAPER|Exercise SECTION - E|13 Videos
  • SAMPLE PAPER 2023 TERM I

    CBSE MODEL PAPER|Exercise SECTION - B|7 Videos
  • SAMPLE PAPER 2022 TERM II

    CBSE MODEL PAPER|Exercise SECTION C|2 Videos
  • SAMPLE PAPER 2024

    CBSE MODEL PAPER|Exercise Question|2 Videos

Similar Questions

Explore conceptually related problems

(a) How does the Hardy- Weinberg's expression (p^(2) + 2pq + q^(2) = 1) explain that genetic equilibrium is maintained in a population ? (b ) List any two factors that can disturb the genetic equilibrium.

According to Hardy-Weinberg's principle, if allele one is denoted as 'A' and allele two as 'a' and their frequencies are denoted by p and q, and if random mating occurs. The frequency of heterozygous individual would be :

pq ^(2) + q (p -1) -1= ?

Add the following expressions: p^2-q +r, q^2 -r+ p and r^2-p+q

Add the following expressions: p^2 - 7pq - q^2 and - 3p^2-2pq + 7q^2

(p-q)^(2)+4pq

In a diploid population at Hardy-Weinberg equilibrium, consider a locus with two alleles. The frequencies of these two alleles are denoted by p and q, respectively. Heterozygosity in this population is maximum at