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25 volume' hydrogen peroxide means...

25 volume' hydrogen peroxide means

A

100 mL marketed solution contains 25 g of `H_2O_2`.

B

1 Lmarketed solution contains 75 g of `H_2O2.`

C

1 L marketed solution contains 250 g of `H_2O_2.`

D

1 L marketed solution contains 25 g of `H_2O_2`

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The correct Answer is:
To solve the question "25 volume hydrogen peroxide means", we need to understand what "25 volume" refers to in the context of hydrogen peroxide (H2O2). ### Step-by-step Solution: 1. **Understanding "Volume" in Chemistry**: - The term "volume" in this context refers to the volume of gas produced by a given volume of liquid solution when it decomposes. Specifically, "25 volume" means that 1 liter of the hydrogen peroxide solution will produce 25 liters of oxygen gas (O2) when it decomposes. 2. **Decomposition Reaction of Hydrogen Peroxide**: - The decomposition of hydrogen peroxide can be represented by the following balanced chemical equation: \[ 2 \text{H}_2\text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2 \] - From this equation, we can see that 2 moles of H2O2 produce 1 mole of O2. 3. **Calculating Moles of O2 Produced**: - At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, if 1 liter of H2O2 produces 25 liters of O2, we can calculate the moles of O2 produced: \[ \text{Moles of O}_2 = \frac{25 \text{ liters}}{22.4 \text{ liters/mole}} \approx 1.116 \text{ moles} \] 4. **Relating Moles of H2O2 to Moles of O2**: - From the balanced equation, we know that 2 moles of H2O2 produce 1 mole of O2. Therefore, the moles of H2O2 required to produce 1.116 moles of O2 is: \[ \text{Moles of H}_2\text{O}_2 = 2 \times 1.116 \approx 2.232 \text{ moles} \] 5. **Calculating Mass of H2O2**: - The molar mass of H2O2 is approximately 34 g/mol. Thus, the mass of H2O2 can be calculated as follows: \[ \text{Mass of H}_2\text{O}_2 = 2.232 \text{ moles} \times 34 \text{ g/mol} \approx 75.89 \text{ grams} \] 6. **Conclusion**: - Therefore, in a 1-liter marketed solution of hydrogen peroxide, there are approximately 75 grams of H2O2. This corresponds to option 2 in the provided choices. ### Final Answer: - **The correct answer is**: 1 liter marketed solution contains 75 gm H2O2.
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20 volume hydrogen peroxide means

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Hydrogen peroxide (H_2 O_2) was first prepared by Thenard by acidifying barium peroxide and removal of excess water by evaporation under reduced pressure. Its strength can be expressed as weigth percentage or as volume percentage . 25% solution by weight means 25 g of hydrogen peroxide are present in 100 g of solution and 25 volume of hydrogen peroxide means that 1 litre of this solution will give 25 L of oxygen at NTP. Why can dilute solution of hydrogen peroxide not be concentrated by heating ?

Hydrogen peroxide (H_2 O_2) was first prepared by Thenard by acidifying barium peroxide and removal of excess water by evaporation under reduced pressure. Its strength can be expressed as weigth percentage or as volume percentage . 25% solution by weight means 25 g of hydrogen peroxide are present in 100 g of solution and 25 volume of hydrogen peroxide means that 1 litre of this solution will give 25 L of oxygen at NTP. Calculated the strength of 25 volume solution of H_2 O_2 .

Hydrogen peroxide (H_2 O_2) was first prepared by Thenard by acidifying barium peroxide and removal of excess water by evaporation under reduced pressure. Its strength can be expressed as weigth percentage or as volume percentage . 25% solution by weight means 25 g of hydrogen peroxide are present in 100 g of solution and 25 volume of hydrogen peroxide means that 1 litre of this solution will give 25 L of oxygen at NTP. Calculate the volume strength of a 2N H_2 O_2 solution.

Hydrogen peroxide (H_2 O_2) was first prepared by Thenard by acidifying barium peroxide and removal of excess water by evaporation under reduced pressure. Its strength can be expressed as weigth percentage or as volume percentage . 25% solution by weight means 25 g of hydrogen peroxide are present in 100 g of solution and 25 volume of hydrogen peroxide means that 1 litre of this solution will give 25 L of oxygen at NTP. Can we use anhydrous barium peroxide for the preparation of H_2 O_2 ?

The volume of oxygen evolved at STP by decomposition of 0.68g '20 volume ' hydrogen peroxide solution is

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