A chloride salt solution acidified with dil `HNO_3` gives a curdy white precipitate,[A] on addition of `AgNO_(3).[A]` on treatment with `NH_(4)OH` gives a clear solution B. `A` and `B` are respectively

Options

A. `H[AgCl_(3)]&(NH_(4))[Ag(OH)_(2)]`
B. `H[AgCl_(3)]&[Ag(NH_(3))_(2)]Cl`
C. `AgCl&[Ag(NH_(3))_(2)]Cl`
D. `AgCl&(NH_(4))[Ag(OH)_(2)]`

Answer

To solve the problem, let's break it down step by step.

### Step 1: Identify the Curdy White Precipitate
When a chloride salt solution is acidified with dilute HNO₃ and then treated with AgNO₃, a curdy white precipitate is formed. This precipitate is silver chloride (AgCl). Therefore, we can denote:
- **A = AgCl**

### Step 2: Treatment with Ammonium Hydroxide
Next, when the precipitate AgCl is treated with ammonium hydroxide (NH₄OH), it dissolves to form a soluble complex. The reaction can be represented as follows:
- AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl

This soluble complex is known as diamminesilver(I) chloride. Therefore, we can denote:
- **B = [Ag(NH₃)₂]Cl**

### Final Answer
Thus, the compounds A and B are:
- **A = AgCl (Silver Chloride)**
- **B = [Ag(NH₃)₂]Cl (Diamminesilver(I) Chloride)**

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