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Let A=([m,n],[p,q]),d=|A| !=0 and |A-d(A...

Let `A=([m,n],[p,q]),d=|A| !=0` and `|A-d(AdjA)|=0`.Then

A

`1+d^(2)=m^(2)+q^(2)`

B

`1+d^(2)=(m+q)^(2)`

C

`(1+d)^(2)=m^(2)+q^(2)`

D

`(1+d)^(2)=(m+q)^(2)`

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The correct Answer is:
D
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