Given below are two statements: Statement : During Electrolytic refining,the pure metal is made to act as anode and its impure metallic form is used as cathode. Statement 1: During the Hal-Hereul electrolysis process,purified `Al_(2)O_(3)` is mixed with `Na_(3)AlF_(6)` to lower the melting point of the mixture. In the light of the above statements,choose the most appropriate answer from the options given below:

Options

A. Both Statement I and Statement II are correct
B. Both Statement I and Statement II are incorrect
C. Statement I is correct but Statement Il is incorrect
D. Statement I is incorrect but Statement II is correct

Answer

To solve the question, we need to analyze the two statements provided:

**Statement 1:** During electrolytic refining, the pure metal is made to act as anode and its impure metallic form is used as cathode.

**Statement 2:** During the Hall-Héroult electrolysis process, purified \( Al_2O_3 \) is mixed with \( Na_3AlF_6 \) to lower the melting point of the mixture.

### Step-by-Step Solution:

1. **Analyzing Statement 1:**
- In electrolytic refining, the process involves using an impure metal as the anode and a pure metal as the cathode.
- The impure metal dissolves into the electrolyte, and pure metal is deposited at the cathode.
- Therefore, the statement that "the pure metal is made to act as anode" is incorrect.

2. **Analyzing Statement 2:**
- The Hall-Héroult process is used for the extraction of aluminum from its ore, where \( Al_2O_3 \) is dissolved in molten cryolite (\( Na_3AlF_6 \)).
- The addition of cryolite lowers the melting point of the mixture and increases its conductivity, making the electrolysis process more efficient.
- Thus, this statement is correct.

3. **Conclusion:**
- Statement 1 is incorrect.
- Statement 2 is correct.
- Therefore, the most appropriate answer is that Statement 1 is false and Statement 2 is true.

### Final Answer:
The correct option is that Statement 1 is incorrect and Statement 2 is correct.

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