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The Wave function (Psi) of 2s is given b...

The Wave function (Psi) of 2s is given by:
`Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0))`
At `r =r_(0)`, radial node is formed . Thus for 2s `,r_(0),` in terms of `a_(0)` is-

A

`r_(0)=a_0/2,`

B

`r_(0)=2a_0`

C

`r_(0)=4a_0`

D

`r_(0)=a_0`

Text Solution

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The correct Answer is:
B
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