An organic compound 'A' with emperical formula `C_(6)H_(6)O` gives sooty flame on burning.Its reaction with bromine solution in low polarity solvent results in high yield of `B.B` is

Options

A.
B.
C.
D.

Answer

To solve the problem, we need to analyze the information given about the organic compound 'A' with the empirical formula C6H6O.

### Step-by-Step Solution:

1. **Identify the Compound 'A':**
- The empirical formula C6H6O suggests that the compound could be an aromatic compound due to the presence of a high hydrogen-to-carbon ratio (C:H = 1:1).
- Given that it burns with a sooty flame, this indicates that it likely contains a benzene ring, as aromatic compounds typically produce sooty flames due to their high carbon content.

2. **Determine the Structure of 'A':**
- The compound with the empirical formula C6H6O that fits the description is phenol (C6H5OH).
- Phenol has a benzene ring with a hydroxyl (–OH) group, which aligns with the empirical formula provided.

3. **Reaction with Bromine:**
- When phenol reacts with bromine in a low polarity solvent (like carbon disulfide, CS2), it undergoes electrophilic aromatic substitution.
- The bromine adds to the aromatic ring, and due to the activating effect of the hydroxyl group, the substitution occurs predominantly at the para position relative to the –OH group.

4. **Identify the Product 'B':**
- The major product formed from the reaction of phenol with bromine in a low polarity solvent is para-bromophenol (C6H4BrOH).
- This is because the para position is favored due to steric and electronic factors.

### Final Answer:
The compound 'B' is para-bromophenol.

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