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H(2)O(2) acts as a reducing agent in...

`H_(2)O_(2)` acts as a reducing agent in

A

`Na_(2)S+4H_(2)O_(2)rarr Na_(2)SO_(4)+4H_(2)O`

B

`Mn^(2+)+2H_(2)O_(2)rarr MnO_(2)+2H_(2)O`

C

`2Fe^(2+)+2H^(+)+H_(2)O_(2)rarr2Fe^(3+)+2H_(2)O`

D

`2NaOCI + H_2O_2 to 2 NaCl + H_2O +O_2`

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The correct Answer is:
To determine in which reaction H₂O₂ (hydrogen peroxide) acts as a reducing agent, we need to analyze the oxidation states of the elements involved in each reaction. A reducing agent is a substance that donates electrons (and thus gets oxidized) during a chemical reaction. ### Step-by-Step Solution: 1. **Identify the Oxidation State of Oxygen in H₂O₂**: - In H₂O₂, the oxidation state of oxygen is -1. 2. **Analyze the Reactions**: - We have four reactions to analyze. We will check the oxidation states of oxygen in the other species involved in each reaction to see if H₂O₂ is oxidized (which would mean it acts as a reducing agent). 3. **Reaction 1**: - If H₂O₂ is reacting with a species where oxygen is in a lower oxidation state (like -2), H₂O₂ cannot act as a reducing agent because it would not be oxidized. - Check the oxidation states of the other reactants and products. If H₂O₂ remains at -1, it is not acting as a reducing agent. 4. **Reaction 2**: - Repeat the same process as in Reaction 1. Check if H₂O₂ is oxidized (the oxidation state of oxygen increases) or remains the same. If it does not oxidize, it is not a reducing agent. 5. **Reaction 3**: - Again, check the oxidation states. If H₂O₂ stays at -1 while the other species are reduced, it is not acting as a reducing agent. 6. **Reaction 4**: - In this reaction, if H₂O₂ is oxidized (the oxidation state of oxygen increases from -1 to 0 in O₂), it indicates that H₂O₂ is donating electrons and thus acting as a reducing agent. - Here, H₂O₂ reduces NaOCl (sodium hypochlorite) to NaCl (sodium chloride) and is oxidized to O₂. 7. **Conclusion**: - Based on the analysis, H₂O₂ acts as a reducing agent in the fourth reaction where it is oxidized from -1 to 0. ### Final Answer: H₂O₂ acts as a reducing agent in the fourth reaction. ---
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