.The correct order of basicity of oxides of vanadium is

Options

A. `V_(2)O_(3)gtV_(2)O_(5)gtV_(2)O_(4)`
B. `V_(2)O_(4)gtV_(2)O_(3)gtV_(2)O_(5)`
C. `V_(2)O_(3)gtV_(2)O_(4)gtV_(2)O_(5)`
D. `V_(2)O_(5)gtV_(2)O_(4)gtV_(2)O_(3)`

Answer

To determine the correct order of basicity of the oxides of vanadium (V), we need to analyze the oxidation states of vanadium in its various oxides and how these states influence basicity.

### Step-by-Step Solution:

1. **Identify the Oxides of Vanadium**: The common oxides of vanadium are V2O3, V2O4, and V2O5.
- V2O3 contains vanadium in the +3 oxidation state.
- V2O4 contains vanadium in the +4 oxidation state.
- V2O5 contains vanadium in the +5 oxidation state.

2. **Understand the Relationship Between Oxidation State and Basicity**:
- Basicity of metal oxides generally decreases with an increase in the oxidation state of the metal. This is because higher oxidation states tend to form more acidic oxides.
- Therefore, V2O3 (V in +3 state) is expected to be the most basic, followed by V2O4 (V in +4 state), and V2O5 (V in +5 state) being the least basic.

3. **Establish the Order of Basicity**:
- Based on the oxidation states:
- V2O3 (most basic, +3 state)
- V2O4 (intermediate basicity, +4 state)
- V2O5 (least basic, +5 state)
- Thus, the order of basicity is: **V2O3 > V2O4 > V2O5**.

4. **Conclusion**: The correct order of basicity of the oxides of vanadium is V2O3 > V2O4 > V2O5.

### Final Answer:
The correct order of basicity of oxides of vanadium is **V2O3 > V2O4 > V2O5**.