Evaluate the following statements for their correctness.
A.The elevation in boiling point temperature of water will be same for `0.1 MNaCl` and `0.1M` urea.
B. Accrogenicxix into`1` without change in their composition.
C. O.Osmosis always takes from hypertonic to hypertonic solution.
D.The density of `32% H_(2)SO_(4)` solution having molarity `4.09M` is approximately `1.26g mL^(-1)`.
E. A negatively charged sol is obtained when `Kl` solution is added to silver nitrate solution.
Choose the correct answer from the options given below :

Options

A. `B` and `D` only `
B. `B,D` and `E` only `
C. `A` and `C` only `
D. A,B` and `C` only `

Answer

To evaluate the correctness of the given statements, let's analyze each one step by step.

### Statement A:
**The elevation in boiling point temperature of water will be the same for 0.1 M NaCl and 0.1 M urea.**

**Analysis:**
- The elevation in boiling point (ΔT_b) is calculated using the formula:
\[ \Delta T_b = i \cdot K_b \cdot m \]
where \(i\) is the van't Hoff factor, \(K_b\) is the ebullioscopic constant, and \(m\) is the molality.
- For NaCl, it dissociates into two ions (Na\(^+\) and Cl\(^-\)), so \(i = 2\).
- For urea, it does not dissociate, so \(i = 1\).
- Therefore, for 0.1 M NaCl, ΔT_b will be greater than that for 0.1 M urea.

**Conclusion:** Statement A is **incorrect**.

### Statement B:
**Azeotropic mixtures boil without changing their composition.**

**Analysis:**
- Azeotropic mixtures have a constant boiling point and maintain the same composition in both the liquid and vapor phases during boiling.
- This is a defining characteristic of azeotropes.

**Conclusion:** Statement B is **correct**.

### Statement C:
**Osmosis always takes place from hypertonic to hypertonic solution.**

**Analysis:**
- Osmosis is the movement of solvent molecules across a semipermeable membrane from a region of lower solute concentration (hypotonic) to a region of higher solute concentration (hypertonic).
- Therefore, the statement is incorrect as it should be from hypotonic to hypertonic.

**Conclusion:** Statement C is **incorrect**.

### Statement D:
**The density of 32% H₂SO₄ solution having molarity 4.09 M is approximately 1.26 g/mL.**

**Analysis:**
- To verify this, we can calculate the density using the given molarity and mass percentage.
- The molar mass of H₂SO₄ is approximately 98 g/mol.
- For a 32% solution, 32 g of H₂SO₄ is present in 100 g of solution.
- The number of moles of H₂SO₄ in 32 g is:
\[ \text{Moles of H₂SO₄} = \frac{32 \text{ g}}{98 \text{ g/mol}} \approx 0.327 \text{ moles} \]
- The volume of the solution can be calculated using the molarity (4.09 M):
\[ \text{Volume} = \frac{\text{Moles}}{\text{Molarity}} = \frac{0.327 \text{ moles}}{4.09 \text{ M}} \approx 0.08 \text{ L} = 80 \text{ mL} \]
- The density can be calculated as:
\[ \text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{100 \text{ g}}{80 \text{ mL}} = 1.25 \text{ g/mL} \]
- This is approximately 1.26 g/mL.

**Conclusion:** Statement D is **correct**.

### Statement E:
**A negatively charged sol is obtained when KI solution is added to silver nitrate solution.**

**Analysis:**
- When KI is added to AgNO₃, a precipitate of AgI is formed, which is neutral. The remaining solution will contain K\(^+\) and NO₃\(^-\) ions.
- The solution does not form a negatively charged sol; it will have positively charged K\(^+\) ions.

**Conclusion:** Statement E is **incorrect**.

### Summary of Statements:
- A: Incorrect
- B: Correct
- C: Incorrect
- D: Correct
- E: Incorrect

### Correct Answers:
The correct statements are **B and D**.