Given below are two statements :
Statement I : Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement II : The green colour observed is due to the formation of copper(I) metaborate In the light of the above statements, choose the most appropriate answer from the options given below :

Options

A. Both Statement I and Statement II are false
B. Both Statement I and Statement II are true
C. Statement I is false but Statement II is true
D. Statement I is true but Statement II is false

Answer

To solve the question, we need to analyze both statements regarding the behavior of a borax bead dipped in cupric sulfate when heated in a luminous flame.

### Step 1: Analyze Statement I
**Statement I:** Upon heating a borax bead dipped in cupric sulfate in a luminous flame, the color of the bead becomes green.

- When a borax bead is heated in a luminous flame, it is expected to undergo a reaction with the cupric sulfate present.
- The cupric sulfate (CuSO₄) is blue in color, and when heated, it can form a different compound.
- In this case, the expected color change is not to green but rather to colorless or a different hue depending on the oxidation state of copper.
- Therefore, **Statement I is false.**

### Step 2: Analyze Statement II
**Statement II:** The green color observed is due to the formation of copper(I) metaborate.

- The formation of copper(I) metaborate (CuBO₂) would typically result in a color change.
- However, the correct observation is that the bead does not turn green; instead, it may turn colorless or red due to the reduction of cupric ions to cuprous ions or metallic copper.
- Since the formation of copper(I) metaborate does not lead to a green color, **Statement II is also false.**

### Conclusion
Based on the analysis of both statements:
- **Both Statement I and Statement II are false.**

### Final Answer
The correct answer is: **Both statements are false.**

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