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Compound A,C(3)H(10)O(5),given a tetraac...

Compound `A,C_(3)H_(10)O_(5)`,given a tetraacetate with `AC_(2)O` and oxidation of `A` with `Br_2-H_(2)O` gives an acid, `C_(5)H_(10)O_(6).` Reduction of `A` with `HI` gives isopentane.The possible structure of `A` is

A

B

C

D

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To solve the problem step by step, we will analyze the information given in the question and derive the possible structure for compound A (C₃H₁₀O₅). ### Step 1: Analyze the Molecular Formula The molecular formula of compound A is C₃H₁₀O₅. This indicates that it contains 3 carbon atoms, 10 hydrogen atoms, and 5 oxygen atoms. ### Step 2: Identify Functional Groups The problem states that compound A forms a tetraacetate when reacted with acetic anhydride (Ac₂O). This suggests that compound A has 4 hydroxyl (–OH) groups, as each –OH group can react with acetic anhydride to form an acetate. ### Step 3: Consider the Oxidation Reaction When compound A is oxidized with Br₂-H₂O, it produces an acid with the formula C₅H₁₀O₆. The increase in carbon atoms from 3 to 5 suggests that the oxidation reaction is likely converting some functional groups into carboxylic acid groups (–COOH). ### Step 4: Analyze the Reduction Reaction The reduction of compound A with HI yields isopentane. Isopentane has the formula C₅H₁₂, which indicates that the reduction process must involve the conversion of functional groups to hydrocarbons. ### Step 5: Determine the Structure of Compound A Given that compound A has 4 hydroxyl groups, a total of 3 carbon atoms, and considering the reactions it undergoes, we can deduce that compound A must be a polyol (a compound with multiple hydroxyl groups). The presence of 4 hydroxyl groups suggests that compound A could be a sugar alcohol or a similar structure. The oxidation to an acid and the reduction to isopentane further suggest that compound A could be a sugar alcohol like D-mannitol or a derivative. ### Step 6: Final Structure Proposal Based on the analysis, the most likely structure for compound A (C₃H₁₀O₅) is a compound that has 4 hydroxyl groups and can be oxidized to yield a compound with a carboxylic acid group. The possible structure of A is: - **A = D-mannitol (C₅H₁₀O₅)** ### Conclusion The possible structure of compound A is one that can react to form tetraacetate, oxidize to an acid, and reduce to isopentane. ---
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Compound (A) C_(5)H_(10)O_(5) give a tetra-acetate with Ac_(2)O and oxidation of (A) with Br_(2)-H_(2)O gives an acid, C_(5)H_(10)O_(6) Reduction of (A) wilh HI and red phosphorous gives 2-methyl butane. What is the structure of (A)?

An organic compound (A) (C_(8)H_(14)O) forms an oxime and gives a positive haloform reaction. On ozonolysis, it gives acetone and a compound (B) (C_(5)H_(8)O_(2)) . (B) forms a dioxime and on subjecting to oxidation reaction gives an acid (C ) (C_(4)H_(6)O_(4)) . On treatment with excess of ammonia and strong heating, (C ) gives a neutral compound (D) (C_(4)H_(5)O_(2)N) . (D) on distillation with zinc dust forms pyrrloe. Suggest the possible structures of (A), (B), (C ), and (D). Explain the chemical reactions involved.

An organic compound (A) of molecular formula C_(5)H_(8) when treated with Na in liquid ammonia followed by reaction with s-Propyl iodide yeidls (B) C_(8)H_(12) (A) gives a ketone C_(5)H_(10)O (e) when treated with dil H_(2)SO_(4) and HgSO_(4) (B) on oxidation with alkaline KMnO_(4) gives two isomeric acids (D) and (E) C_(4)H_(8)O_(2) . Give structures of compounds (A) to (E) with proper reasoning .

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