Reaction of propanamide with `Br_(2)`/`KOH` (aq) produces:

Options

A. Propanenitrile
B. Ethylamine
C. Propylamine
D. Ethylnitrile

Answer

To solve the problem of what products are formed when propanamide reacts with Br₂/KOH, we can follow these steps:

### Step 1: Identify the Structure of Propanamide
Propanamide is an amide with the formula CH₃CH₂C(O)NH₂. It consists of a three-carbon chain with an amine functional group.

### Step 2: Understand the Reaction Conditions
The reaction involves bromine (Br₂) and potassium hydroxide (KOH) in an aqueous solution. This combination is known to facilitate the Hofmann degradation reaction.

### Step 3: Recall the Hofmann Degradation Mechanism
Hofmann degradation involves the conversion of an amide to a primary amine with one less carbon atom. This reaction typically results in the loss of the carbonyl carbon.

### Step 4: Apply the Mechanism to Propanamide
When propanamide (CH₃CH₂C(O)NH₂) undergoes Hofmann degradation:
- The carbonyl carbon (C=O) is lost.
- The remaining structure after losing one carbon will be CH₃CH₂NH₂.

### Step 5: Identify the Product
The product CH₃CH₂NH₂ corresponds to ethylamine, which is a primary amine.

### Conclusion
Thus, the reaction of propanamide with Br₂/KOH produces ethylamine.

### Final Answer
The product of the reaction of propanamide with Br₂/KOH is ethylamine (C₂H₅NH₂).

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